去评论
推扬网

邓芝:x^(x+1)-y(xy+x) 因式分解 要完整详细的过程

admin
2020/08/11 18:01:13

活好今天的回答:

=x(x^+x-y^-Y) =X(X+Y)(X-Y)^

活好今天的回答:

=x(x^+x-y^-Y) =X(X+Y)(X-Y)^

嵿尖уě蠻的回答:

x^(x+1)-y(xy+x) =x^2+x-xy^2-xy =x(x+1-y^2-y)

LEAD C-R-H的回答:

=x(x^+x-y^-Y) =x((x-y)(x+y)+x-y) =x(x-y)(x+y+1)