潘燕雯的回答:tanx-secx
=sinx/conx?-1/cosx
=(sinx-1)/cosx
tanx与secx的关系式为
想吃猫的鱼的回答:左=(cosx+1+sinx)/(cosx+1-sinx).右=(1+sinx)/cosx. (cosx+1+sinx)cosx=cos2x+cosx+sinxcosx. (1+sinx)(cosx+1-sinx)=cosx+1-sinx+sinxcosx+sinx-sin2x =cos2x+cosx+sinxcosx. 所以 :(1+secx+tanx)/(1+secx-tanx)=secx+tanx。 刘彦红的回答:tanx -secx=sinx/cosx-1/cosx=(sinx-1)/cosx =-(cosx/2-sinx/2)^回2 /[ (cosx/2)^2-(sinx/2)^2] =-(cosx/2-sinx/2) /( cosx/2+sinx/2) =-(1-tanx/2)/(1+tanx/2) =-(tanπ答/4-tanx/2)/(1+tanπ/4*tanx/2) =-tan(π/4-x/2) =tan(x/2-π/4) |