只需一步,快速开始
2020-8-10 20:19| 发布者: admin| 查看: 84| 评论: 0
cos2X=cos2X-sin2X =2cos2X-1 =1-2sin2X
cos2X=(cosX)^2-(sinX)^2 =2*(cosX)^2-1
sinxcosxcos2x
=(1/2)2sinxcosxcos2x
=(1/2)sin2xcos2x
=(1/4)sin4x
=2cos2x-1
设cos2x等于n个cosx: cos2x=ncosx 解得: n=(cos2x)/cosx
评论
广告服务|投稿要求|禁言标准|版权说明|免责声明|手机版|小黑屋|推扬网 ( 粤ICP备18134897号 )|网站地图 | 邮箱:vayae@hotmail.com
GMT+8, 2025-6-15 09:22 , Processed in 0.062114 second(s), 28 queries .
Powered by Discuz! X3.4
© 2001-2017 Comsenz Inc.