推扬网

 找回密码
 立即注册

QQ登录

只需一步,快速开始

搜索
推扬网 门户 你问我答 查看内容

王倩懿:求高数求导公式大全!!!

2020-8-12 17:17| 发布者: admin| 查看: 157| 评论: 0

摘要: 张宝珠的回答: f'(c) = 0f'(x^n) = nx^(x-1)f'(1/x) = -1/x^2f'(√x) = 1/2√xf'(㏑x) = 1/xf'(㏒ax) = 1/x㏑a (a为底)f'(a^x) = a^x * ㏑af'(e^x) = e^xf&#3 ...

张宝珠的回答:

f'(c) = 0f'(x^n) = nx^(x-1)f'(1/x) = -1/x^2f'(√x) = 1/2√xf'(㏑x) = 1/xf'(㏒ax) = 1/x㏑a (a为底)f'(a^x) = a^x * ㏑af'(e^x) = e^xf'(sinx) = cosxf'(cosx) = -sinxf'(tanx) = (sec^2)x = 1/(cos^2)xf'(cotx) = -(csc^2)x = -1/(sin^2)xf'(secx) = cesx * tanxf'(cscx) = -cscx * cotxf'(arcsinx) = 1/√(1-x^2)f'(arccosx) = -1/√(1-x^2)f'(arctanx) = 1/1+x^2

汪琳的回答:

f'(c) = 0f'(x^n) = nx^(x-1)f'(1/x) = -1/x^2f'(√x) = 1/2√xf'(㏑x) = 1/xf'(㏒ax) = 1/x㏑a (a为底)f'(a^x) = a^x * ㏑af'(e^x) = e^xf'(sinx) = cosxf'(cosx) = -sinxf'(tanx) = (sec^2)x = 1/(cos^2)xf'(cotx) = -(csc^2)x = -1/(sin^2)xf'(secx) = cesx * tanxf'(cscx) = -cscx * cotxf'(arcsinx) = 1/√(1-x^2)f'(arccosx) = -1/√(1-x^2)f'(arctanx) = 1/1+x^2


鲜花

握手

雷人

路过

鸡蛋

最新评论

热门推荐
最新资讯

广告服务|投稿要求|禁言标准|版权说明|免责声明|手机版|小黑屋|推扬网 ( 粤ICP备18134897号 )|网站地图 | 邮箱:vayae@hotmail.com

GMT+8, 2025-5-1 11:57 , Processed in 0.060063 second(s), 29 queries .

Powered by Discuz! X3.4

© 2001-2017 Comsenz Inc.

返回顶部