聂宁的回答：private static int count=1; public int digui(int a,int b){ int c=a+b; count++; if(count <= 30){ digui(b,c); } return c; } 杨近川的回答：private static int count=1; public int digui(int a,int b){ int c=a+b; count++; if(count <= 30){ digui(b,c); } return c; } 许伟的回答：public static int Add(int i) { if(i<=0) { return 0; } else if(i>0 && i<=2) { return 1; } else { return Add(i-1)+Add(i-2); } } 王思远的回答：f(x)＝f(x-1)+f(x-2) 设f(0)=1 设f(1)=1 然后就好了 int f(x) { if(x==0||x==1)return 1; else return f(x-1)+f(x-2); } 没调试过＾＾ 言艺的回答：using System; using System.Collections.Generic; using System.Text; namespace Consoleapplication2 { class Program { static void Main(string[] args) { int[] num=new int[30]; num[0] = 1; num[1] = 1; System.Console.Write(num[0] + " " + num[1] + " "); for (int i = 0; i < 28; i++) { num[i + 2] = num[i+1] + num[i]; System.Console.Write(num[i+2]+" "); } System.Console.Read(); } } } |
