赵颖的回答：设甲种鱼苗为x尾，乙种鱼苗为(6000-x)尾 0.5x＋0.8×(6000-x)≤4200 0.3x>=600 x>2000 设甲种鱼苗为x尾，乙种鱼苗为(6000-x)尾 90%x＋95%×(6000-x)≥93%*6000 0.05x<=0.02*6000 x<=2400 张锐轩的回答：设甲种鱼苗为x尾，乙种鱼苗为(6000-x)尾 0.5x＋0.8×(6000-x)≤4200 0.3x>=600 x>2000 设甲种鱼苗为x尾，乙种鱼苗为(6000-x)尾 90%x＋95%×(6000-x)≥93%*6000 0.05x<=0.02*6000 x<=2400 |
